Joint Entrance Examination (JEE) 2013 for Admission to Undergraduate Engineering Programmes in IITs, NITs and other Technical Institutions

Central Board of Secondary Education has notified that admission to Undergraduate Engineering Programmes in IITs, NITs and other Centrally Funded Technical Institutions will be based on a Joint Entrance Examination (JEE) with effect from 2013.

JEE will be conducted in two parts – JEE (Main) and JEE (Advanced).

JEE (Main) will replace AIEEE and JEE (Advanced) will replace IIT-JEE, with the important criterion that only the top 150,000 candidates performing in JEE (Main) will qualify for appearing in JEE (Advanced). Admission to IITs, IT-BHU and ISM Dhanbad will be based only on category-wise All India Rank in JEE (Advanced), subject to the additional condition that such candidates are in the top 20 percentile of successful candiates in Class XII/equivalent examination conducted by their Boards.

For admission to Undergraduate Engineering Programmes in NITs and other Centrally Funded Technical Institutions the rank list will be prepared based on 40% weightage to school board marks in Class XII and 60% weightage to JEE (Main) marks.

JEE (Main) 2013 Paper I (for admission to B.E./B.Tech courses) which replaces Paper I of earlier AIEEE, will be of 3 hours, consisting of objective type questions from Physics, Chemistry and Mathematics.

Paper II for admission to B.Arch/B.Planning courses also will be of 3 hours and will consist of Mathematics, Aptitude Test and Drawing Test as per past practice of AIEEE.

The JEE (Main) (Paper I of earlier AIEEE) for B.E./B.Tech will be held in two modes, viz., offline and online (CBT). The offline examination for JEE (Main) will be conducted on 7^th April, 2013 and the online examinations will be conducted thereafter in April, 2013.

For details you may visit http://jeemain.nic.in 

CBSE to conduct National Eligibility Cum Entrance Test (NEET) 2013 for admission to MBBS and BDS Courses

“The pursuit of truth and beauty is a sphere of activity in which we are permitted to remain children all our lives.”

– Albert Einstein

Most of the students aspiring for admission to MBBS and BDS courses in India will be happy about the recent notification that admission to MBBS and BDS Courses in the institutions approved by the Medical Council of India and Dental Council of India are subject to merit position of candidates in the National Eligibility Cum Entrance Test (Under-Graduate), 2013.

The Central Board of Secondary Education (C.B.S.E.) will conduct the National Eligibility cum Entrance Test (NEET) for admission to MBBS and BDS Courses on Sunday, the 5^th May 2013.

The syllabus for the National Eligibility cum Entrance Test (NEET) is available on the Medical Council of India website www.mciindia.org

Lorentz force – An IIT-JEE 2012 Multiple Correct Answer(s) Type Question

“Making the simple complicated is commonplace; making the complicated simple, awesomely simple, that’s creativity.”

– Charles Mingus    

IIT-JEE Multiple Correct Answer(s) Type Questions are designed to have four choices (A), (B), (C) and (D) out of which ONE or MORE are correct. The following question appeared in IIT-JEE 2012 question paper. The question is meant for checking your understanding of Lorentz forces.

Consider the motion of a positive point charge in a region where there are simultaneous uniform electric and magnetic fields E = E₀ ĵ and B = B₀ ĵ. At time t = 0, this charge has velocity v in the x-y plane, making an angle θ with the x-axis. Which of the following option(s) is (are) correct for t > 0?

(A) If θ = 0°, the charge moves in a circular path in the x-z plane.

(B) If θ = 0°, the charge undergoes helical motion with constant pitch along the y-axis.

(C) If θ = 10°, the charge undergoes helical motion with its pitch increasing with time, along the y-axis.

(D) If θ = 90°, the charge undergoes linear but accelerated motion along the y-axis.

Note that the electric and magnetic fields are along the positive y-direction.

If θ = 0, the charged particle is moving at right angles to the electric and magnetic fields (Fig.). The magnetic force (qv×B₀) will make the particle move along a circle and the electric force (qE₀) will push it along the positive y-direction. The path of the particle will therefore be a helix of increasing pitch.

If θ = 10°,the magnetic field will make the particle move along the positive y-direction, following a helical path of constant pitch; but since the electric force (qE₀) pushes it along the positive y-direction, the helical path has increasing pitch.

If θ = 90°, the charged particle is moving parallel to the electric and magnetic fields. The magnetic field has no action on the motion since there is no magnetic force. But the electric force (qE₀) will push the particle along the positive y-direction. The particle is thus in accelerated linear motion. 

Therefore options (C) and (D) are correct.